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manual: Fix MathJax typo

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Thanks to @cafkafk for catching my mistake.
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John Ericson 2025-11-05 11:08:36 -05:00
parent 948c89b367
commit 91af29f37a
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10
doc/manual/source/store/build-trace.md
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@ -40,13 +40,13 @@ Unlike with base build traces, incoherence with derived build traces is possible
The key ingredient is that derivation resolution is only deterministic with respect to a fixed base build trace. The key ingredient is that derivation resolution is only deterministic with respect to a fixed base build trace.
Without fixing the base build trace, it inherits the subjectivity of base build traces themselves. Without fixing the base build trace, it inherits the subjectivity of base build traces themselves.
Concretely, suppose there are three derivations \\(a\\), \\(b\\), and \((c\\). Concretely, suppose there are three derivations \\(a\\), \\(b\\), and \\(c\\).
Let \\(a\\) be a resolved derivation, but let \\(b\\) and \((c\\) be unresolved and both take as an input an output of \\(a\\). Let \\(a\\) be a resolved derivation, but let \\(b\\) and \\(c\\) be unresolved and both take as an input an output of \\(a\\).
Now suppose that derived entries are made for \\(b\\) and \((c\\) based on two different entries of \\(a\\). Now suppose that derived entries are made for \\(b\\) and \\(c\\) based on two different entries of \\(a\\).
(This could happen if \\(a\\) is non-deterministic, \\(a\\) and \\(b\\) are built in one store, \\(a\\) and \\(c\\) are built in another store, and then a third store substitutes from both of the first two stores.) (This could happen if \\(a\\) is non-deterministic, \\(a\\) and \\(b\\) are built in one store, \\(a\\) and \\(c\\) are built in another store, and then a third store substitutes from both of the first two stores.)
If trusting the derived build trace entries for \\(b\\) and \((c\\) requires that each's underlying entry for \\(a\\) be also trusted, the two different mappings for \\(a\\) will be caught. If trusting the derived build trace entries for \\(b\\) and \\(c\\) requires that each's underlying entry for \\(a\\) be also trusted, the two different mappings for \\(a\\) will be caught.
However, if \\(b\\) and \((c\\)'s entries can be combined in isolation, there will be nothing to catch the contradiction in their hidden assumptions about \\(a\\)'s output. However, if \\(b\\) and \\(c\\)'s entries can be combined in isolation, there will be nothing to catch the contradiction in their hidden assumptions about \\(a\\)'s output.
[derivation]: ./derivation/index.md [derivation]: ./derivation/index.md
[output]: ./derivation/outputs/index.md [output]: ./derivation/outputs/index.md